(5x+1)^2/3=9

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Solution for (5x+1)^2/3=9 equation:


x in (-oo:+oo)

((5*x+1)^2)/3 = 9 // - 9

((5*x+1)^2)/3-9 = 0

((5*x+1)^2)/3+(-9*3)/3 = 0

(5*x+1)^2-9*3 = 0

25*x^2+10*x-26 = 0

25*x^2+10*x-26 = 0

25*x^2+10*x-26 = 0

DELTA = 10^2-(-26*4*25)

DELTA = 2700

DELTA > 0

x = (2700^(1/2)-10)/(2*25) or x = (-2700^(1/2)-10)/(2*25)

x = (30*3^(1/2)-10)/50 or x = (-30*3^(1/2)-10)/50

(x-((-30*3^(1/2)-10)/50))*(x-((30*3^(1/2)-10)/50)) = 0

((x-((-30*3^(1/2)-10)/50))*(x-((30*3^(1/2)-10)/50)))/3 = 0

((x-((-30*3^(1/2)-10)/50))*(x-((30*3^(1/2)-10)/50)))/3 = 0 // * 3

(x-((-30*3^(1/2)-10)/50))*(x-((30*3^(1/2)-10)/50)) = 0

( x-((-30*3^(1/2)-10)/50) )

x-((-30*3^(1/2)-10)/50) = 0 // + (-30*3^(1/2)-10)/50

x = (-30*3^(1/2)-10)/50

( x-((30*3^(1/2)-10)/50) )

x-((30*3^(1/2)-10)/50) = 0 // + (30*3^(1/2)-10)/50

x = (30*3^(1/2)-10)/50

x in { (-30*3^(1/2)-10)/50, (30*3^(1/2)-10)/50 }

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